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Bohr operator on operator-valued polyanalytic functions on simply connected domains

Published online by Cambridge University Press:  26 June 2023

Vasudevarao Allu*
Affiliation:
School of Basic Sciences, Indian Institute of Technology Bhubaneswar, Bhubaneswar 752050, India
Himadri Halder
Affiliation:
Mathematics Department, Indian Institute of Technology Bombay, Mumbai 400076, India e-mail: himadrihalder119@gmail.com, himadri@math.iitb.ac.in
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Abstract

In this article, we study the Bohr operator for the operator-valued subordination class $S(f)$ consisting of holomorphic functions subordinate to f in the unit disk $\mathbb {D}:=\{z \in \mathbb {C}: |z|<1\}$, where $f:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ is holomorphic and $\mathcal {B}(\mathcal {H})$ is the algebra of bounded linear operators on a complex Hilbert space $\mathcal {H}$. We establish several subordination results, which can be viewed as the analogs of a couple of interesting subordination results from scalar-valued settings. We also obtain a von Neumann-type inequality for the class of analytic self-mappings of the unit disk $\mathbb {D}$ which fix the origin. Furthermore, we extensively study Bohr inequalities for operator-valued polyanalytic functions in certain proper simply connected domains in $\mathbb {C}$. We obtain Bohr radius for the operator-valued polyanalytic functions of the form $F(z)= \sum _{l=0}^{p-1} \overline {z}^l \, f_{l}(z) $, where $f_{0}$ is subordinate to an operator-valued convex biholomorphic function, and operator-valued starlike biholomorphic function in the unit disk $\mathbb {D}$.

Type
Article
Copyright
© The Author(s), 2023. Published by Cambridge University Press on behalf of The Canadian Mathematical Society

1 Introduction

Let $H^{\infty }(\mathbb {D})$ be the space of bounded analytic functions from the unit disk $\mathbb {D}:=\{z \in \mathbb {C}:|z|<1\}$ into the complex plane $\mathbb {C}$ and denote $\left \lVert f\right \rVert _{\infty }:=\sup _{|z|<1} |f(z)|$ . In $1914$ , the following remarkable result for the universal constant $r=1/3$ for functions in $H^{\infty }(\mathbb {D})$ was proved by Bohr [Reference Bohr13].

Theorem A Let $f \in H^{\infty }(\mathbb {D})$ with the power series $f(z)=\sum _{n=0}^{\infty } a_{n}z^{n}$ . Then

(1.1) $$ \begin{align} \sum_{n=0}^{\infty} |a_{n}|r^{n} \leq \left\lVert f\right\rVert_{\infty} \end{align} $$

for $|z|=r \leq 1/3$ , and the constant $1/3$ , referred to as the classical Bohr radius, is the best possible.

The interest in the Bohr inequality has been revived when Dixon [Reference Dixon15] used it to disprove the conjecture that if the nonunital von Neumann’s inequality holds for a Banach algebra, then it is necessarily an operator algebra. In $2004$ , Paulsen and Singh [Reference Paulsen and Singh22] extended Bohr’s theorem to Banach algebras by finding a general version of Bohr inequality which is valid in the context of uniform algebras. For fixed $z\in \mathbb {D}$ , we denote

$$ \begin{align*} \mathcal{G}_{z}:= \left\{f(z)=\sum_{n=0}^{\infty} a_{n}z^n: f\in H^{\infty}(\mathbb{D}) \right\}. \end{align*} $$

For $|z|=r$ , the Bohr operator $M_{r}$ on $\mathcal {G}_{z}$ is defined by

$$ \begin{align*} M_{r}(f)= \sum_{n=0}^{\infty} |a_{n}| |z^n|= \sum_{n=0}^{\infty} |a_{n}| r^n. \end{align*} $$

The Bohr operator has the following properties, which has been established in [Reference Paulsen and Singh23].

Theorem 1.1 [Reference Abu Muhanna, Ali, Ng and Lee2]

For each fixed $z \in \mathbb {D}$ and $|z|=r$ , the Bohr operator $M_{r}$ satisfies:

  1. (1) $M_{r}(f) \geq 0$ , and $M_{r}(f)=0$ if, and only if, $f\equiv 0$ ,

  2. (2) $M_{r}(f+g) \leq M_{r}(f)+M_{r}(g)$ ,

  3. (3) $M_{r}(\alpha f)= |\alpha | M_{r}(f)$ , $\alpha \in \mathbb {C}$ ,

  4. (4) $M_{r}(f.g)\leq M_{r}(f).M_{r}(g)$ ,

  5. (5) $M_{r}(1)=1$ .

By the virtue of Theorem 1.1, it is worth to mention that the space $\mathcal {G}_{z}$ with the norm $M_{r}$ constitutes a Banach algebra. However, not all Banach spaces satisfy the Bohr phenomenon. In [Reference BÉnÉteau, Dahlner and Khavinson7], Bénéteau et al. have shown that $H^{q}$ , the usual Hardy spaces in $\mathbb {D}$ , do not satisfy the Bohr phenomenon for any $0<q<\infty $ . A complex Banach algebra $\mathcal {A}$ satisfies the von Neumann inequality if for all polynomial $p(X)$ and for all $x \in \mathcal {A}$ with $\left \lVert x\right \rVert \leq 1$ ,

(1.2) $$ \begin{align} \left\lVert p(x)\right\rVert \leq \left\lVert p\right\rVert_{\infty}. \end{align} $$

In [Reference von Neumann25], von Neumann has shown that the algebra $\mathcal {B}(\mathcal {H})$ of all bounded operators on a Hilbert space $\mathcal {H}$ satisfies the inequality (1.2). It is well known that every Banach algebra which is an operator algebra (i.e., which is isometrically isomorphic to a closed subalgebra of $\mathcal {B}(\mathcal {H})$ for some Hilbert space $\mathcal {H}$ ) also satisfies the von Neumann inequality (1.2). Bohr inequality has been extended to several complex variables and more abstract settings (see [Reference Aytuna and Djakov8, Reference Boas and Khavinson12, Reference Defant, García, Maestre and Pérez-García14, Reference Hamada, Honda and Kohr19, Reference Paulsen, Popescu and Singh21, Reference Paulsen and Singh22, Reference Popescu24]).

Another interesting aspect of Bohr phenomenon thrives on considering the Bohr radius problem for subordinating families of analytic functions in $\mathbb {D}$ . For two analytic functions g and f in $\mathbb {D}$ , we say that g is subordinate to f, written $g \prec f$ , if there exists an analytic function $\phi :\mathbb {D} \rightarrow \mathbb {D}$ with $\phi (0)=0$ such that $g(z)=f(\phi (z))$ in $\mathbb {D}$ . Let $S(f)$ be the class of analytic functions subordinate to f in $\mathbb {D}$ . We say that g is quasi-subordinate to f if there exists an analytic function $\psi $ with $|\psi (z)|\leq 1$ in $\mathbb {D}$ such that $g(z)=\psi (z)f(\phi (z))$ in $\mathbb {D}$ . It is well known that if g is subordinate (or quasi-subordinate) to f in $\mathbb {D}$ , then $M_{r}(g) \leq M_{r}(f)$ for $|z|=r \leq 1/3$ . Bhowmik and Das [Reference Bhowmik and Das10] have studied the Bohr radius for the subordinating families, and the Bohr radius for quasi-subordination families has been studied by Alkhaleefah et al. [Reference Alkhaleefah, Kayumov and Ponnusamy5]. In $2021$ , Bhowmik and Das [Reference Bhowmik and Das11] extended the Bohr phenomenon for the subordination to operator-valued analytic functions in $\mathbb {D}$ . Throughout this article, $\mathcal {B}(\mathcal {H})$ stands for the space of bounded linear operators on a complex Hilbert space $\mathcal {H}$ . We want to concentrate operator-valued holomorphic functions $f:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ . The term subordination for operator-valued functions can be defined as the scalar valued case. That is, for two holomorphic functions $g,f:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ , we say that g is subordinate to f, written $g \prec f$ , if there exists a holomorphic function $\phi :\mathbb {D} \rightarrow \mathbb {D}$ with $\phi (0)=0$ such that $g(z)=f(\phi (z))$ in $\mathbb {D}$ . Let $S(f)$ be the class of analytic functions subordinate to f in $\mathbb {D}$ . For given two Banach spaces X and Y and a domain $\Omega \subset X$ , a holomorphic function $f :\Omega \rightarrow Y$ is said to be biholomorphic on $\Omega $ if $f^{-1}$ exists and is holomorphic in $f(\Omega ) \subseteq Y$ . We say that a biholomorphic function f is starlike in its domain $\Omega $ with respect to $\xi _{0} \in \Omega $ if $f(\Omega )$ is a starlike domain with respect to $f(\xi _{0})$ , i.e., $(1-t) f(\xi _{0}) + tf(z) \in f(\Omega )$ for all $z \in \Omega $ and $t \in [0,1]$ . A biholomorphic function f is called starlike if f is starlike with respect to $0\in \Omega $ and $f(0)=0$ . A biholomorphic function f is said to be convex if f is starlike with respect to every point in $\Omega $ . For convex or star-like biholomorphic function f in $\mathbb {D}$ , Bohr phenomenon for any $g \in S(f)$ has been studied in [Reference Bhowmik and Das11].

For the rest of our discussion, we introduce some notations. Throughout this paper, $\left \lVert A\right \rVert $ stands for the operator norm of A for any $A\in \mathcal {B}(\mathcal {H})$ and $\left \lvert A\right \rvert =(A^{*}A)^{1/2}$ denotes the absolute value of A, where $A^{*}$ is the adjoint of A and $T^{1/2}$ denotes the unique positive square root of a positive operator T. We denote I be the identity operator on $\mathcal {H}$ .

In $2010$ , Fournier and Ruscheweyh [Reference Fournier and Ruscheweyh16] extensively studied the Bohr radius problem for arbitrary simply connected domains containing $\mathbb {D}$ . Let $\mathcal {H}(\Omega )$ be the class of analytic functions $f : \Omega \rightarrow \mathbb {C}$ , and let $\mathcal {B}(\Omega )$ denote the class of functions $f \in \mathcal {H}(\Omega )$ such that $f(\Omega ) \subseteq \overline {\mathbb {D}}$ . For the class $\mathcal {B}(\Omega )$ , the Bohr radius $\mathcal {B}_{\Omega }$ is defined by (see [Reference Ahamed, Allu and Halder4, Reference Fournier and Ruscheweyh16])

$$\begin{align*}B_{\Omega}:=\sup\bigg\{r\in (0,1) : M_{r}(f)\leq 1\; \text{for all}\; f(z)=\sum_{n=0}^{\infty}a_nz^n\in\mathcal{B}(\Omega),\; z\in\mathbb{D}\bigg\}, \end{align*}$$

where $M_{r}(f):=\sum _{n=0}^{\infty }|a_n|r^n$ is the Bohr operator for $f \in \mathcal {B}(\Omega )$ in $\mathbb {D}$ . For $\Omega =\mathbb {D}$ , $\mathcal {B}(\Omega )$ reduces to $B_{\mathbb {D}}=1/3$ , which is the classical Bohr radius for the class $\mathcal {B}(\mathbb {D})$ .

For $0\leq \gamma <1$ , Fournier and Ruscheweyh [Reference Fournier and Ruscheweyh16] have estimated the Bohr radius for the class $\mathcal {B}(\Omega _{\gamma })$ and proved that $\mathcal {B}_{\Omega _{\gamma }}=(1+\gamma )/(3+\gamma )$ , where

$$\begin{align*}\Omega_{\gamma}:=\bigg\{z\in\mathbb{C} : \bigg|z+\frac{\gamma}{1-\gamma}\bigg|<\frac{1}{1-\gamma}\bigg\}. \end{align*}$$

Let $H^{\infty }(\Omega ,X)$ be the space of bounded analytic functions from $\Omega $ into a complex Banach space X and $\left \lVert f\right \rVert _{H^{\infty }(\Omega ,X)}= \sup _{z \in \Omega } \left \lVert f(z)\right \rVert $ . The Bohr phenomenon for operator-valued functions on simply connected domains has been studied in [Reference Allu and Halder6]. Let $\mathcal {B}(\mathcal {H})$ be the algebra of all bounded linear operators on a complex Hilbert space $\mathcal {H}$ . For the class $H^{\infty }(\Omega ,\mathcal {B}(\mathcal {H}))$ , we denote (see [Reference Allu and Halder6])

(1.3) $$ \begin{align} \lambda_{\mathcal{H}}:=\lambda_{\mathcal{H}}(\Omega):= \sup \limits _{\substack{f \in H^{\infty}(\Omega,\mathcal{B}(\mathcal{H}))\\{\left\lVert f(z)\right\rVert\leq1}}} \left\{\frac{\left\lVert A_{n}\right\rVert}{\left\lVert\, I- |A_{0}|^2\right\rVert\,} : A_{0} \not \equiv f(z)= \sum \limits_{n=0}^{\infty} A_{n} z^n, \,\, z \in \mathbb{D}\right\}. \end{align} $$

Recently, Allu and Halder [Reference Allu and Halder6] have established the Bohr theorem for the functions in $H^{\infty }(\Omega ,\mathcal {B}(\mathcal {H}))$ .

Theorem 1.2 [Reference Allu and Halder6]

Let $f \in H^{\infty }(\Omega ,\mathcal {B}(\mathcal {H}))$ with $\left \lVert f(z)\right \rVert _{H^{\infty }(\Omega ,\mathcal {B}(\mathcal {H}))} \leq 1$ such that $f(z)= \sum _{n=0}^{\infty } A_{n}z^n$ in $\mathbb {D}$ , where $A_{0}=\alpha _{0}I$ for $|\alpha _{0}|<1$ and $A_{n} \in \mathcal {B}(\mathcal {H})$ for all $n \in \mathbb {N} \cup \{0\}$ . Then

(1.4) $$ \begin{align} \sum_{n=0}^{\infty} \left\lVert A_{n}\right\rVert r^n \leq 1 \,\,\,\,\,\, \mbox{for} \,\,\,\, r \leq \frac{1}{1+2\lambda_{\mathcal{H}}}. \end{align} $$

For $\Omega =\Omega _{\gamma }$ and $p=1$ in [Reference Allu and Halder6, Corollary 1.52], we have the following result.

Theorem 1.3 [Reference Allu and Halder6]

Let $f \in H^{\infty }(\Omega _{\gamma },\mathcal {B}(\mathcal {H}))$ with $\left \lVert f(z)\right \rVert _{H^{\infty }(\Omega _{\gamma },\mathcal {B}(\mathcal {H}))} \leq 1$ such that $f(z)= \sum _{n=0}^{\infty } A_{n}z^n$ in $\mathbb {D}$ , where $A_{0}=\alpha _{0}I$ for $|\alpha _{0}|<1$ and $A_{n} \in \mathcal {B}(\mathcal {H})$ for all $n \in \mathbb {N} \cup \{0\}$ . Then

(1.5) $$ \begin{align} \sum_{n=0}^{\infty} \left\lVert A_{n}\right\rVert r^n \leq 1 \,\,\,\,\,\, \mbox{for} \,\,\,\, r \leq \frac{1+\gamma}{3+\gamma}. \end{align} $$

When $\Omega _{\gamma }=\mathbb {D}$ , i.e., $\gamma =0$ , under the same assumptions as in Theorem 1.3, we have

(1.6) $$ \begin{align} \sum_{n=0}^{\infty} \left\lVert A_{n}\right\rVert r^n \leq 1 \,\,\,\,\,\, \mbox{for} \,\,\,\, r \leq \frac{1}{3}. \end{align} $$

2 Bohr operator on operator-valued subordination classes

In this section, we study subordination results for Bohr operator on operator-valued analytic functions in $\mathbb {D}$ . Recall that $\mathcal {B}(\mathcal {H})$ be the algebra of all bounded linear operators on a complex Hilbert space $\mathcal {H}$ . For analytic functions $f:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ with $f(z)= \sum _{n=0}^{\infty } A_{n} z^n$ in $\mathbb {D}$ and $A_{n} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ , we define the Bohr operator $M_{r}(f)$ as the scalar valued case. That is, $M_{r}(f)= \sum _{n=0}^{\infty } \left \lVert A_{n}\right \rVert |z|^n$ . It can be easily seen that the operator $M_{r}$ satisfies the same property as in Theorem 1.1. In fact, for $f,g :\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ with $f(z)= \sum _{n=0}^{\infty } A_{n} z^n$ and $g(z)= \sum _{n=0}^{\infty } B_{n} z^n$ in $\mathbb {D}$ with $A_{n}, B_{n} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ , we have

(2.1) $$ \begin{align} M_{r}(f+g) = \sum_{n=0}^{\infty} \left\lVert A_{n}+B_{n}\right\rVert r^n \leq \sum_{n=0}^{\infty} \left\lVert A_{n}\right\rVert r^n + \sum_{n=0}^{\infty} \left\lVert B_{n}\right\rVert r^n= M_{r}(f) + M_{r}(g). \end{align} $$

Using (2.1), it is easy to see that if $F(z)= \sum _{k\in \mathbb {Z}} f_{k}(z)$ is analytic function in $\mathbb {D}$ , then $M_{r}(F) \leq \sum _{k\in \mathbb {Z}} M_{r}(f_{k})$ , where $f_{k}: \mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ is analytic function in $\mathbb {D}$ for each $k \in \mathbb {Z}$ . On the other hand, we note that $M_{r}(\beta f)= |\beta |M_{r}(f)$ for any $\beta \in \mathbb {C}$ and $M_{r}(z^pf)=r^p M_{r}(f)$ . We observe that $(fg)(z)=\sum _{n=0}^{\infty } A_{n} (z^n g(z))$ and hence

(2.2) $$ \begin{align} M_{r}(fg) \leq \sum_{n=0}^{\infty} \left\lVert A_{n}\right\rVert r^n M_{r}(g)= M_{r}(f)M_{r}(g). \end{align} $$

Clearly, $M_{r}(I)=1$ . The following result has been established in [Reference Abu Muhanna, Ali, Ng and Lee2].

Lemma 2.3 [Reference Abu Muhanna, Ali, Ng and Lee2]

Let $\phi :\mathbb {D} \rightarrow \mathbb {D}$ be analytic function with $\phi (0)=0$ . Then $M_{r}(\phi ) \leq |z|$ for $|z|=r \leq 1/3$ .

The following result is the operator-valued subordination result for Bohr operator, which has been first proved in [Reference Bhowmik and Das11]. By using Lemma 2.3, we give an alternative proof.

Theorem 2.1 Let $f,g:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ be holomorphic functions such that $f \prec g$ . Then

(2.4) $$ \begin{align} M_{r}(f) \leq M_{r}(g)\,\,\,\,\,\,\,\,\, \mbox{for} \,\,\, |z|=r\leq \frac{1}{3}. \end{align} $$

Proof Let $f(z)= \sum _{n=0}^{\infty } A_{n} z^n$ and $g(z)= \sum _{n=0}^{\infty } B_{n} z^n$ in $\mathbb {D}$ with $A_{n}, B_{n} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ . Since $f \prec g$ in $\mathbb {D}$ , then there exists an analytic function $\phi :\mathbb {D} \rightarrow \mathbb {D}$ such that $\phi (0)=0$ and $f(z)=g(\phi (z))$ in $\mathbb {D}$ . In view of (2.1), (2.2), and Lemma 2.3, for $0\leq |z|=r\leq 1/3$ , we obtain

$$ \begin{align*} M_{r}(f)=M_{r}(g(\phi))&=M_{r}\left(\sum_{n=0}^{\infty}B_{n}(\phi(z))^n\right) \\& \leq \sum_{n=0}^{\infty} \left\lVert B_{n}\right\rVert(M_{r}(\phi(z)))^n \leq \sum_{n=0}^{\infty} \left\lVert B_{n}\right\rVert r^n=M_{r}(g). \end{align*} $$

This completes the proof.

In particular, for the scalar-valued functions $f,g:\mathbb {D} \rightarrow \mathbb {C}$ , Theorem 2.1 reduces to the result of Abu Muhanna et al. [Reference Abu Muhanna, Ali, Ng and Lee2], and Bhowmik and Das [Reference Bhowmik and Das10]. In view of Theorem 2.1, we obtain the following interesting result.

Theorem 2.2 Let $f,g,h:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ be holomorphic functions such that $f(z)=h(z)g(\phi (z))$ for some analytic function $\phi :\mathbb {D} \rightarrow \mathbb {D}$ with $\phi (0)=0$ . If $\left \lVert h(z)\right \rVert \leq M$ for $|z|<\beta \leq 1$ and $h(0)=\alpha I$ with $|\alpha | \leq M$ , then $M_{r}(f) \leq M \, M_{r}(g)$ for $0 \leq r \leq \beta /3$ .

Proof From (2.2), we have

(2.5) $$ \begin{align} M_{r}(f) \leq M_{r}(h) M_{r}(g(\phi)). \end{align} $$

The assumption $\left \lVert h(z)\right \rVert \leq M$ in the disk $\mathbb {D}_{\beta }:=\{z \in \mathbb {C}:|z|<\beta \}$ shows that $h_{1}:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ defined by $h_{1}(z)=h(z)/M$ is holomorphic and $\left \lVert h_{1}(z)\right \rVert \leq 1$ in $\mathbb {D}_{\beta }$ such that $h_{1}(0)=(\alpha /M)I$ . Since $|\alpha | \leq M$ , from (1.6), we obtain

(2.6) $$ \begin{align} M_{r}(h) \leq M \,\,\,\,\,\mbox{for} \,\,\,\, 0<r\leq \frac{\beta}{3}. \end{align} $$

Furthermore, in view of Theorem 2.1, we have

(2.7) $$ \begin{align} M_{r}(g(\phi)) \leq M_{r}(g) \,\,\,\,\,\mbox{for} \,\,\,\, 0<r\leq\frac{1}{3}. \end{align} $$

By using (2.6) and (2.7) in (2.5), we obtain

(2.8) $$ \begin{align} M_{r}(f) \leq M\,\, M_{r}(g) \,\,\,\,\,\mbox{for} \,\,\,\, 0<r\leq \frac{\beta}{3}. \end{align} $$

This completes the proof.

Remark 2.1

  1. (1) For a particular case $h(z)\equiv I$ , Theorem 2.2 reduces to Theorem 2.1. By taking $f,g,h :\mathbb {D} \rightarrow \mathbb {C}$ are analytic functions in Theorem 2.2, we obtain the scalar-valued quasi-subordination result, which has been established in [Reference Alkhaleefah, Kayumov and Ponnusamy5].

  2. (2) When $\left \lVert h(z)\right \rVert \leq 1$ in $\mathbb {D}$ , we deduce that $M_{r}(f) \leq M_{r}(g)$ for $|z|=r \leq 1/3$ .

We now prove the following interesting result, which is an analog of von Neumann inequality (1.2).

Theorem 2.3 Let $f:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ be analytic in $\mathbb {D}$ and continuous in $\overline {\mathbb {D}}$ such that $f(0)=\alpha I$ for some $\alpha \in \mathbb {C}$ with $|\alpha |<1$ . Then

(2.9) $$ \begin{align} M_{r}(f(\phi)) \leq \left\lVert f\right\rVert_{\infty} \,\,\,\, \mbox{for} \,\,\,\,\, 0\leq r \leq 1/3, \end{align} $$

where $\phi : \mathbb {D} \rightarrow \mathbb {D}$ is analytic function with $\phi (0)=0$ .

Proof Let $f(z)= \sum _{n=0}^{\infty } A_{n} z^n$ in $\mathbb {D}$ , where $A_{0}=\alpha I$ and $A_{n} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ . Then, for $r \leq 1/3$ , Theorem 2.1 gives

(2.10) $$ \begin{align} M_{r}(f(\phi)) \leq \sum_{n=0}^{\infty} \left\lVert A_{n}\right\rVert r^n= M_{r}(f). \end{align} $$

In view of (1.6), for $0\leq r \leq 1/3$ , we obtain $M_{r}(f) \leq \left \lVert f\right \rVert _{\infty }$ which together with (2.10) gives (2.9).

3 Bohr theorem for operator-valued polyanalytic functions

Polyanalytic functions f of order p defined in a simply connected domain $\Omega \subseteq \mathbb {C}$ are complex-valued polynomials in the variable $\overline {z}$ with analytic functions are their coefficients. That is, f has the following form $ f(z)= \sum _{l=0}^{p-1} \overline {z}^p \, f_{l}(z), $ where $f_{l}$ ’s are analytic functions in $\Omega $ . Equivalently, polyanalytic functions can also be defined as the $\mathcal {C}^p(\Omega )$ -solutions of the generalized Cauchy–Riemann equations $\partial ^{p} f/ \partial \overline {z}^p=0$ in $\Omega $ (the Cauchy–Riemann equations of order p). Throughout this paper, we assume that $p \geq 2$ .

In $1908$ , Kolossov [Reference Kolossov20] first introduced polyanalytic functions in connection with his research in the mathematical theory of elasticity. Polyanalytic function theory has been extensively studied by Balk [Reference Balk, Gonchar, Havin and Nikolski9]. In $2011$ , Agranovsky [Reference Agranovsky3] characterized the polyanalytic functions by meromorphic extensions into chains of circles. It is worth mentioning that the properties of polyanalytic functions can be different from those of analytic functions (see [Reference Balk, Gonchar, Havin and Nikolski9]). By considering the polyanalytic function $f(z)=1-z\overline {z}$ , one can easily see that f vanishes on the boundary of the unit disk $\mathbb {D}$ without vanishing identically in $\mathbb {D}$ . Studying polyanalytic functions also reveals some new properties of analytic functions. The study of polyanalytic functions is closely related to numerous research topics of complex analysis, e.g., function theory of several complex variables, the theory of distribution of values of meromorphic functions, the theory of meromorphic curves, and the theory of boundary properties of analytic functions. In $2019$ , Hachadi and Youssfi [Reference Hachadi and Youssfi18] have studied several properties of polyanalytic reproducing kernels. In $2021$ , Abdulhadi and Hajj [Reference Abdulhadi and Hajj1] extensively studied univalency criteria, Landau’s theorem, arc-length problem, and the Bohr phenomenon problem for polyanalytic functions in $\mathbb {D}$ .

Since complex-valued polyanalytic functions are polynomials in $\overline {z}$ in simply connected domain $\Omega $ , this leads to study the operator-valued polyanalytic functions. A operator-valued polyanalytic function F of order p in $\Omega $ is a polynomial in $\overline {z}$ with operator-valued analytic functions as its coefficients. That is, F has the following form:

$$ \begin{align*} F(z)= \sum_{l=0}^{p-1} \overline{z}^p \, f_{l}(z), \end{align*} $$

where $f_{l}: \Omega \rightarrow \mathcal {B}(\mathcal {H})$ are analytic functions for $l=0,1, \ldots , p-1$ and $f_{p-1} \not \equiv 0$ . Now, we consider the simply connected domain $\Omega $ containing $\mathbb {D}$ .

Although Bohr radius and Bohr phenomenon have been extensively studied, no attempt has been made so far to obtain operator-valued analogs of Bohr phenomenon for polyanalytic functions. Therefore, our main aim of this section is to obtain the Bohr inequality under appropriate considerations and necessary conditions. In the following result, we establish operator-valued analogs of Bohr inequality in simply connected domain $\Omega $ containing $\mathbb {D}$ .

Theorem 3.1 Let F be a polyanalytic function of order p in $\Omega $ with $F(z)= \sum _{l=0}^{p-1} \overline {z}^l \, f_{l}(z) $ , where each $f_{l}: \Omega \rightarrow \mathcal {B}(\mathcal {H})$ is an analytic function such that $f_{l}(z)= \sum _{n=0}^{\infty } A_{n,l} z^n$ in $\mathbb {D}$ and $A_{n,l} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ . Also, assume that:

  1. (a) $\left \lVert f_{0}(z)\right \rVert \leq 1$ in $\Omega $ such that $f_{0}(0)=\mathbf {0}$ and $f^{\prime }_{l}(0)=\alpha _{l} f^{\prime }_{0}(0)$ with $|\alpha _{l}| <k$ for $k \in [0,1]$ and each $l=1,\ldots , p-1$ .

  2. (b) $\omega _{l} : \Omega \rightarrow \mathcal {B}(\mathcal {H})$ is analytic with $\left \lVert \omega _{l}(z)\right \rVert \leq k$ in $\Omega $ for $k \in [0,1]$ , where $\omega _{l}(z)= f^{\prime }_{l}(z) (f^{\prime }_{0}(z))^{-1}$ in $\Omega $ such that $\omega _{l}(z)=\sum _{n=0}^{\infty } \omega _{n,l} z^n $ in $\mathbb {D}$ , provided $(f^{\prime }_{0}(z))^{-1}$ exists for all $z \in \Omega $ .

Then $M_{r}(F) \leq 1$ for $|z|=r \leq R_{f}= \min \{r_{f}(p), 1/(1+2\lambda _{\mathcal {H}})\}$ , where $r_{f}(p)$ is the smallest root in $(0,1)$ of

(3.1) $$ \begin{align} (1-r)^2 - k\lambda_{\mathcal{H}}\, r +k\lambda_{\mathcal{H}}\, r^{p+1}=0. \end{align} $$

Here, $\lambda _{\mathcal {H}}$ is given by (1.3).

Proof Let $F(z)= \sum _{l=0}^{p-1} \overline {z}^l \, f_{l}(z) $ with $f_{l}(z)= \sum _{n=0}^{\infty } A_{n,l} \,z^n$ in $\mathbb {D}$ . Then

(3.2) $$ \begin{align} M_{r}(F)= M_{r} \left(\sum_{l=0}^{p-1} \overline{z}^l \, f_{l}(z)\right) \leq \sum_{l=0}^{p-1} r^l M_{r}(f_{l}) \,\,\,\,\, \mbox{for} \,\,\,\, |z|=r<1. \end{align} $$

Since $\omega _{l}(z)=f^{\prime }_{l}(z) (f^{\prime }_{0}(z))^{-1}$ in $\Omega $ with $\left \lVert \omega _{l}(z)\right \rVert \leq k$ in $\Omega $ for each l such that $f^{\prime }_{l}(0)=\alpha _{l} f^{\prime }_{0}(0)$ , it follows that $f^{\prime }_{l}(z)= \omega _{l}(z) f^{\prime }_{0}(z)$ in $\Omega $ with $\omega _{l}(0)=\alpha _{l}I$ , where $|\alpha _{l}|<k$ for each $l=1, \ldots , p-1$ . Let $\lambda _{\mathcal {H}}$ be given by (1.3). In view of Theorem 1.2, for $|z|=r \leq 1/(1+2\lambda _{\mathcal {H}})$ , we have $M_{r}(\omega _{l}) \leq k$ , which together with (2.2) gives

(3.3) $$ \begin{align} M_{r}(f_{l})= \int \limits_{0}^{r} M_{r}(f^{\prime}_{l})dt= \int\limits_{0}^{r} M_{r}(\omega_{l}f^{\prime}_{0})dt \leq k\,\int\limits_{0}^{r} M_{r}(f^{\prime}_{0})dt =k\, M_{r}(f_{0}). \end{align} $$

Using (3.2) and (3.3), for $|z|=r \leq 1/(1+2\lambda _{\mathcal {H}})$ , we obtain

(3.4) $$ \begin{align} M_{r}(F) \leq k\sum_{l=0}^{p-1} r^l M_{r}(f_{0}) = k M_{r}(f_{0}) \left(\frac{1-r^p}{1-r}\right). \end{align} $$

We now wish to find the upper bound for $M_{r}(f_{0})$ . We observe that $f_{0}: \Omega \rightarrow \mathcal {B}(\mathcal {H})$ is analytic function with $\left \lVert f_{0}(z)\right \rVert \leq 1$ in $\Omega $ such that $f_{0}(z)= \sum _{n=0}^{\infty } A_{n,0} z^n$ in $\mathbb {D}$ , where $f_{0}(0)=A_{0,0}=\mathbf {0}$ . Then, in view of (1.3), we have $\left \lVert A_{n,0}\right \rVert \leq \lambda _{\mathcal {H}}$ for $n \geq 1$ , and hence

(3.5) $$ \begin{align} M_{r}(f_{0}) = \sum_{n=0}^{\infty} \left\lVert A_{n,0}\right\rVert\, r^n \leq \lambda_{\mathcal{H}} \left(\frac{r}{1-r}\right). \end{align} $$

In view of (3.4) and (3.5), for $r \leq 1/(1+2\lambda _{\mathcal {H}})$ , we obtain

(3.6) $$ \begin{align} M_{r}(F) \leq k \, \lambda_{\mathcal{H}}\left( \frac{r}{1-r}\right) \left(\frac{1-r^p}{1-r}\right). \end{align} $$

Therefore, $M_{r}(F) \leq 1$ for $r \leq \min \{1/(1+2\lambda _{\mathcal {H}}), r_{f}(p)\}$ , where $r_{f}(p)$ is the smallest root in $(0,1)$ of

$$\begin{align*}k\, \lambda_{\mathcal{H}}\left( \frac{r}{1-r}\right) \left(\frac{1-r^p}{1-r}\right) = 1, \end{align*}$$

which is equivalent to $(1-r)^2 -k\, \lambda _{\mathcal {H}}\,r + k\,\lambda _{\mathcal {H}}\, r^{p+1}=0$ . This completes the proof.

As a consequence of Theorem 3.1, we obtain Bohr-type inequality for bi-analytic functions in a domain $\Omega $ .

Corollary 3.7 Let F be a bi-analytic function in a domain $\Omega $ with the series expansion as in Theorem 3.1. Also, assume all the hypotheses as in Theorem 3.1. Then $M_{r}(F)\leq 1$ for $|z|=r \leq \min \{r_{f}(2), 1/(1+2\lambda _{\mathcal {H}})\}$ , where $r_{f}(2)$ is the smallest root in $(0,1)$ of

(3.8) $$ \begin{align} (1-r)^2 - k\lambda_{\mathcal{H}}\, r + k\lambda_{\mathcal{H}}\, r^{3}=0, \end{align} $$

where $\lambda _{\mathcal {H}}$ is given by (1.3).

For $\Omega =\Omega _{\gamma }$ , we have $\lambda _{\mathcal {H}}=\lambda _{\mathcal {H}}(\Omega _{\gamma })\leq 1/(1+\gamma )$ (see [Reference Allu and Halder6]). In view of Theorem 3.1, we obtain the following corollaries.

Corollary 3.9 Let F be a polyanalytic function in $\Omega _{\gamma }$ with the series expansion as in Theorem 3.1. Also, assume all the hypotheses as in Theorem 3.1. Then $M_{r}(F)\leq 1$ for $|z|=r \leq \min \{r_{f}(p,\gamma ), (1+\gamma )/(3+\gamma )\}$ , where $r_{f}(p,\gamma )$ is the smallest root in $(0,1)$ of

(3.10) $$ \begin{align} (1+\gamma)(1-r)^2 - kr + k r^{p+1}=0. \end{align} $$

The following result is the limiting case of Corollary 3.9. Consider the domain $\tilde {\Omega }=\{z: {\operatorname {Re}\,} z<1\}$ , which can be obtained as the limiting case of the domain $\Omega _{\gamma }$ by considering $\gamma \rightarrow 1^{-}$ .

Corollary 3.11 Let F be a polyanalytic function in $\tilde {\Omega }$ with the series expansion as in Theorem 3.1. Also, assume all the hypotheses as in Theorem 3.1. Then $M_{r}(F)\leq 1$ for $|z|=r \leq \min \{r_{f}(p,1), 1/2\}$ , where $r_{f}(p,1)$ is the smallest root in $(0,1)$ of

(3.12) $$ \begin{align} 2(1-r)^2 - kr + k r^{p+1}=0. \end{align} $$

In the next result, we obtain Bohr radius for the polyanalytic function $F(z)= \sum _{l=0}^{p-1} \overline {z}^l \, f_{l}(z) $ , where $f_{0}$ is a subordinate to a convex biholomorphic function in the unit disk $\mathbb {D}$ .

Theorem 3.2 Let F be a polyanalytic function of order p in $\mathbb {D}$ with $F(z)= \sum _{l=0}^{p-1} \overline {z}^l \, f_{l}(z) $ , where each $f_{l}: \mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ is an analytic function such that $f_{l}(z)= \sum _{n=0}^{\infty } A_{n,l} z^n$ in $\mathbb {D}$ and $A_{n,l} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ . Also, assume that:

  1. (1) $f_{0} \in S(g)$ such that $f_{0}(0)=\mathbf {0}$ and $f^{\prime }_{l}(0)=\alpha _{l} f^{\prime }_{0}(0)$ with $|\alpha _{l}| <k$ for $k \in [0,1]$ and each $l=1,\ldots , p-1$ , where $g:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ is a convex biholomorphic function with $g(z)= \sum _{n=0}^{\infty } g_{n} z^n$ in $\mathbb {D}$ and $g_{n} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ .

  2. (2) $\omega _{l} : \mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ is an analytic function with $\left \lVert \omega _{l}(z)\right \rVert \leq k$ in $\mathbb {D}$ for $k \in [0,1]$ , where $\omega _{l}(z)= f^{\prime }_{l}(z) (f^{\prime }_{0}(z))^{-1}$ in $\mathbb {D}$ such that $\omega _{l}(z)=\sum _{n=0}^{\infty } \omega _{n,l} z^n $ in $\mathbb {D}$ , provided $(f^{\prime }_{0}(z))^{-1}$ exists for all $z \in \mathbb {D}$ .

Then $M_{r}(F) \leq 1$ for $|z|=r \leq R_{C}= \min \{r_{C}(p,k,\beta ), 1/3\}$ , where $r_{C}(p,k,\beta )$ is the smallest root in $(0,1)$ of

(3.13) $$ \begin{align} (1-r)^2 -k \beta\, r + k \beta\, r^{p+1}=0, \end{align} $$

where $\left \lVert g'(0)\right \rVert =\beta $ .

Proof From (3.4), it is enough to estimate the upper bound of $M_{r}(f_{0})$ . Let $g: \mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ be univalent and convex biholomorphic function in $\mathbb {D}$ such that $g(z)=\sum _{n=0}^{\infty } g_{n}z^n$ , where $g_{n} \in \mathcal {B}(\mathcal {H})$ . Set $\xi = e^{2\pi i/n}$ . Since g is convex, then by the similar argument used in proving [Reference Rogosinski26, Theorem X], we obtain

$$ \begin{align*} \Psi(z^n)= \frac{f_{0}(\xi z)+f_{0}(\xi^2 z)+ \cdots + f_{0}(\xi^n z)}{n}=A_{n,0}z^n + A_{2n,0}z^{2n}+ \cdots \prec g(z), \end{align*} $$

and hence $\Psi (z)=A_{n,0}z + A_{2n,0}z^{2}+ \cdots \prec g(z)$ for $z \in \mathbb {D}$ . Hence, there exits a holomorphic function $\omega : \mathbb {D} \rightarrow \mathbb {D}$ with $\omega (0)=0$ such that $\Psi (z)=g(\omega (z))$ , which implies that $\Psi '(0)=\omega '(0)g'(0)$ . That is, $A_{n,0}=\omega '(0)g'(0)$ , which leads to

(3.14) $$ \begin{align} \left\lVert A_{n,0}\right\rVert \leq \left\lVert g'(0)\right\rVert. \end{align} $$

Since $f_{l}(z)= \sum _{n=0}^{\infty } A_{n,l} z^n$ in $\mathbb {D}$ , using (3.14) and the fact $f_{0}(0)=\mathbf {0}$ , we obtain

(3.15) $$ \begin{align} M_{r}(f_{0})=\sum_{n=0}^{\infty}\left\lVert A_{n,0}\right\rVert r^n \leq \left(\frac{r}{1-r}\right) \, \left\lVert g'(0)\right\rVert=\beta \left(\frac{r}{1-r}\right). \end{align} $$

Since $F(z)= \sum _{l=0}^{p-1} \overline {z}^l \, f_{l}(z) $ with $f_{l}(z)= \sum _{n=0}^{\infty } A_{n,l} \,z^n$ in $\mathbb {D}$ , we have

(3.16) $$ \begin{align} M_{r}(F)= M_{r} \left(\sum_{l=0}^{p-1} \overline{z}^l \, f_{l}(z)\right) \leq \sum_{l=0}^{p-1} r^l M_{r}(f_{l}) \,\,\,\,\, \mbox{for} \,\,\,\, |z|=r<1. \end{align} $$

By the given assumption $\omega _{l}(z)=f^{\prime }_{l}(z) (f^{\prime }_{0}(z))^{-1}$ in $\Omega $ with $\left \lVert \omega _{l}(z)\right \rVert \leq k$ in $\Omega $ for each l such that $f^{\prime }_{l}(0)=\alpha _{l} f^{\prime }_{0}(0)$ , it follows that $f^{\prime }_{l}(z)= \omega _{l}(z) f^{\prime }_{0}(z)$ in $\Omega $ with $\omega _{l}(0)=\alpha _{l}I$ , where $|\alpha _{l}|<k$ for each $l=1, \ldots , p-1$ . Let $\lambda _{\mathcal {H}}$ be given by (1.3). For $\Omega _{\gamma }=\mathbb {D}$ , i.e., $\gamma =0$ , we have $\lambda _{\mathcal {H}} \leq 1$ (see [Reference Allu and Halder6]). In view of Theorem 1.2, for $|z|=r \leq 1/3$ , we have $M_{r}(\omega _{l}) \leq k$ , which together with (2.2) gives

(3.17) $$ \begin{align} M_{r}(f_{l})= \int \limits_{0}^{r} M_{r}(f^{\prime}_{l})dt= \int\limits_{0}^{r} M_{r}(\omega_{l}f^{\prime}_{0})dt \leq k\,\int\limits_{0}^{r} M_{r}(f^{\prime}_{0})dt =k\, M_{r}(f_{0}). \end{align} $$

Using (3.15)–(3.17), for $|z|=r \leq 1/3$ , we obtain

(3.18) $$ \begin{align} M_{r}(F) \leq k\sum_{l=0}^{p-1} r^l M_{r}(f_{0}) = k M_{r}(f_{0}) \left(\frac{1-r^p}{1-r}\right) \leq k \beta \left(\frac{r}{1-r}\right) \left(\frac{1-r^p}{1-r}\right). \end{align} $$

Hence, $M_{r}(F) \leq 1$ for $r \leq R_{C}= \min \{r_{C}(p,k,\beta ), 1/3\}$ , where $r_{C}(p,k,\beta )$ is the smallest root in $(0,1)$ of (3.13). This completes the proof.

Let $h:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ be holomorphic and $g \in S(h)$ with the expansions $h(z)=\sum _{n=0}^{\infty } h_{n}z^n$ and $g(z)=\sum _{n=0}^{\infty } g_{n}z^n$ , respectively, in $\mathbb {D}$ , where $h_{n},g_{n} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ . Then, in view of [Reference Bhowmik and Das11, Lemma 2], for $|z|=r\leq 1/3$ , it is known that

(3.19) $$ \begin{align} \sum_{n=1}^{\infty} \left\lVert g_{n}\right\rVert r^n \leq \sum_{n=1}^{\infty} \left\lVert h_{n}\right\rVert r^n. \end{align} $$

In the following result, we obtain Bohr radius for the polyanalytic function $F(z)= \sum _{l=0}^{p-1} \overline {z}^l \, f_{l}(z) $ , where $f_{0}$ is subordinate to a starlike biholomorphic function in the unit disk $\mathbb {D}$ .

Theorem 3.3 Let F be a polyanalytic function of order p in $\mathbb {D}$ with $F(z)= \sum _{l=0}^{p-1} \overline {z}^l \, f_{l}(z) $ , where each $f_{l}: \mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ are analytic functions such that $f_{l}(z)= \sum _{n=0}^{\infty } A_{n,l} z^n$ in $\mathbb {D}$ and $A_{n,l} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ . Also, assume that:

  1. (1) $f_{0} \in S(g)$ such that $f_{0}(0)=\mathbf {0}$ and $f^{\prime }_{l}(0)=\alpha _{l} f^{\prime }_{0}(0)$ with $|\alpha _{l}| <k$ for $k \in [0,1]$ and each $l=1,\ldots , p-1$ , where $g:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ is a normalized starlike biholomorphic function with $g(z)= zI+\sum _{n=2}^{\infty } g_{n} z^n$ in $\mathbb {D}$ and $g_{n} \in \mathcal {B}(\mathcal {H})$ for $n \in \mathbb {N} \cup \{0\}$ .

  2. (2) $\omega _{l} : \mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ is an analytic function with $\left \lVert \omega _{l}(z)\right \rVert \leq k$ in $\mathbb {D}$ for $k \in [0,1]$ , where $\omega _{l}(z)= f^{\prime }_{l}(z) (f^{\prime }_{0}(z))^{-1}$ in $\mathbb {D}$ such that $\omega _{l}(z)=\sum _{n=0}^{\infty } \omega _{n,l} z^n $ in $\mathbb {D}$ .

Then $M_{r}(F) \leq 1$ for $|z|=r \leq R_{S}= \min \{r_{S}(p,k), 1/3\}$ , where $r_{s}(p,k)$ is the smallest root in $(0,1)$ of

(3.20) $$ \begin{align} (1-r)^3 -k r + k r^{p+1}=0. \end{align} $$

Proof Let $g:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ be a normalized starlike biholomorphic function. Then, in view of [Reference Graham and Kohr17, Theorem 6.2.6], g satisfies

(3.21) $$ \begin{align} z\, g'(z)= q(z)g(z)\,\,\,\,\,\,\mbox{for} \,\,\,\, z \in \mathbb{D}, \end{align} $$

where $q:\mathbb {D} \rightarrow \mathbb {C}$ is an analytic function with ${\operatorname {Re}\,} q(z)>0$ in $\mathbb {D}$ and $q(0)=1$ . By comparing the coefficients in the power series of both the sides of (3.21), we obtain

(3.22) $$ \begin{align} (n-1)g_{n} = g_{n-1}q_{1} + g_{n-2}q_{2}+\cdots + q_{n-1}\,\,\,\,\,\, \mbox{for} \,\,\,\, n\geq 2. \end{align} $$

By using induction and (3.22), we obtain

$$ \begin{align*} (n-1) \left\lVert g_{n}\right\rVert \leq 2(n-1+n-2+\cdots+1)I=n(n-1)I, \end{align*} $$

which turns out that $\left \lVert g_{n}\right \rVert \leq n$ for all $n \geq 2$ . Since, $f_{0} \in S(g)$ , by using (3.19), for $r\leq 1/3$ , we obtain

(3.23) $$ \begin{align} M_{r}(f_{0})=\sum_{n=1}^{\infty} \left\lVert A_{n,0}\right\rVert r^n \leq \sum_{n=1}^{\infty} \left\lVert g_{n}\right\rVert r^n \leq r+ \sum_{n=2}^{\infty} nr^n=\frac{r}{(1-r)^2}. \end{align} $$

It is known that, for $\Omega _{\gamma }=\mathbb {D}$ , i.e., $\gamma =0$ , if $h:\mathbb {D} \rightarrow \mathcal {B}(\mathcal {H})$ is holomorphic, then we have $\lambda _{\mathcal {H}} \leq 1$ (see [Reference Allu and Halder6]). From (3.17), we have

(3.24) $$ \begin{align} M_{r}(f_{l}) \leq k\, M_{r}(f_{0}). \end{align} $$

Then, from (3.16), (3.23), and (3.24), we obtain

$$ \begin{align*} M_{r}(F) \leq k\, \frac{r}{(1-r)^2} \left(\frac{1-r^p}{1-r}\right)\,\,\,\, \mbox{for} \,\,\,\, r \leq \frac{1}{3}. \end{align*} $$

Hence, $M_{r}(F) \leq 1$ for $r \leq R_{S}= \min \{r_{S}(p,k), 1/3\}$ , where $r_{C}(p,k,\beta )$ is the smallest root in $(0,1)$ of (3.20). This completes the proof.

Acknowledgment

The authors would like to express their sincerest gratitude to the referees for careful reading of the manuscript and many valuable suggestions, which greatly helped to improve the clarity of the exposition in this manuscript.

Competing interests

The authors declare none.

Footnotes

The first-named author is supported by SERB-CRG, and the second-named author is supported by the Institute Postdoctoral Fellowship of IIT Bombay, India.

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