Given a tetrahedron of reference ABCD, let λ, μ, ν, π be the cosines of the angles made by a line with the perpendiculars to the faces BCD, ACD, ABD, ABC respectively, these perpendiculars being drawn all inwards or all outwards; where
Aλ1 + Bμ1 + C½1 + Dπ1 = 0
Aλ2 + Bμ2 + C½2 + Dπ2 = 0
A, B, C, D being the areas of the faces BCD, .. If P1 (α1, ²1, γ1, δ1) and P2 (α2, β2, γ2, δ2) are any two points, the lines PP1 and PP2 can be written
(α - α1)/λ1 = (β - β1)/μ1 = (γ - γ1)/ν1 = (δ - δ1)/π1 = θ1,
(α - α2)/λ2 = (β - β2)/μ2 = (γ - γ2)/ν2 = (δ - δ2)/π2 = θ2,
to find the cosine of the angle between PP1 and PP2.