Hostname: page-component-cd9895bd7-q99xh Total loading time: 0 Render date: 2024-12-27T22:09:54.916Z Has data issue: false hasContentIssue false

BEARDON'S DIOPHANTINE EQUATIONS AND NON-FREE MÖBIUS GROUPS

Published online by Cambridge University Press:  01 May 2000

ALEKSANDER GRYTCZUK
Affiliation:
Institute of Mathematics, Pedagogical University (WSP), Pl. Słowiański 9, 65-069 Zielona Góra, Poland
MAREK WÓJTOWICZ
Affiliation:
Institute of Mathematics, Pedagogical University (WSP), Pl. Słowiański 9, 65-069 Zielona Góra, Poland
Get access

Abstract

Let μ be a real number. The Möbius group Gμ is the matrix group generated by

formula here

It is known that Gμ is free if [mid ]μ[mid ] [ges ] 2 (see [1]) or if μ is transcendental (see [3, 8]). Moreover, there is a set of irrational algebraic numbers μ which is dense in (−2,2) and for which Gμ is non-free [2, p. 528]. We may assume that μ > 0, and in this paper we consider rational μ in (0, 2). The following problem is difficult.

formula here

Let [Gscr ] denote the set of all rational numbers μ in (0, 2) for which Gμ is non-free. In 1969 Lyndon and Ullman [8] proved that [Gscr ]nf contains the elements of the forms p/(p2 + 1) and 1/(p + 1), where p = 1, 2, …, and that if μ0 ∈ [Gscr ]nf then μ0/p ∈ [Gscr ]nf for p = 1, 2, …. In 1993 Beardon [2] studied problem (P) by means of the words of the form ArBsAt and ArBsAtBuAv, and he obtained a sufficient condition for solvability of (P), included implicitly in [2, pp. 530–531], by means of the following Diophantine equations:

formula here

Type
NOTES AND PAPERS
Copyright
© The London Mathematical Society 2000

Access options

Get access to the full version of this content by using one of the access options below. (Log in options will check for institutional or personal access. Content may require purchase if you do not have access.)