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The Metric Dimension of Circulant Graphs

Published online by Cambridge University Press:  20 November 2018

Tomáš Vetrík*
Affiliation:
Department of Mathematics and Applied Mathematics, University of the Free State, Bloemfontein, South Africa e-mail: vetrikt@ufs.ac.za
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Abstract

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Abstract. A subset $W$ of the vertex set of a graph $G$ is called a resolving set of $G$ if for every pair of distinct vertices $u,\,v$, of $G$, there is $w\,\in \,W$ such that the distance of $w$ and $u$ is different from the distance of $w$ and $v$. The cardinality of a smallest resolving set is called the metric dimension of $G$, denoted by $\dim\left( G \right)$. The circulant graph ${{C}_{n}}\left( 1,\,2,\,.\,.\,.\,,\,t \right)$ consists of the vertices ${{v}_{0}},\,{{v}_{1\,}},\,.\,.\,.\,,{{v}_{n\,-\,1}}$ and the edges ${{v}_{i}}{{v}_{i\,+\,j}}$, where $0\,\le \,i\,\le \,n\,-\,1,1\,\le \,j\,\le \,t\,\left( 2\,\le \,t\,\le \,\left\lfloor \frac{n}{2} \right\rfloor \right)$, the indices are taken modulo $n$. Grigorious, Manuel, Miller, Rajan, and Stephen proved that $\dim\left( {{C}_{n}}\left( 1,\,2,\,.\,.\,.\,,\,t \right) \right)\,\ge \,t\,+\,1$ for $t\,<\,\left\lfloor \frac{n}{2} \right\rfloor ,\,n\,\ge \,3$, and they presented a conjecture saying that $\dim\left( {{C}_{n}}\left( 1,\,2,\,.\,.\,.\,,\,t \right) \right)\,=\,t\,+\,p\,-\,1$ for $n\,=\,2tk\,+\,t\,+\,p$, where $3\,\le \,p\,\le \,t\,+\,1$. We disprove both statements. We show that if $t\,\ge \,4$ is even, there exists an infinite set of values of $n$ such that $\dim\left( {{C}_{n}}\left( 1,\,2,\,.\,.\,.\,,t \right) \right)\,=\,t$. We also prove that $\dim\left( {{C}_{n}}\left( 1,\,2,\,.\,.\,.\,,\,t \right) \right)\,\le \,t\,+\,\frac{p}{2}$ for $n\,=\,2tk\,+\,t\,+\,p$, where $t$ and $p$ are even, $t\,\ge \,4,\,2\,\le \,p\,\le \,t$, and $k\,\ge \,1$.

Type
Research Article
Copyright
Copyright © Canadian Mathematical Society 2017

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