Book contents
- Frontmatter
- Contents
- Foreword by Jan Mycielski
- Preface
- Preface to the Paperback Edition
- Part I Paradoxical Decompositions, or the Nonexistence of Finitely Additive Measures
- Part II Finitely Additive Measures, or the Nonexistence of Paradoxical Decompositions
- Appendix A Euclidean Transformation Groups
- Appendix B Jordan Measure
- Appendix C Unsolved Problems
- Addendum to Second Printing
- References
- List of Symbols
- Index
Appendix C - Unsolved Problems
Published online by Cambridge University Press: 05 August 2012
- Frontmatter
- Contents
- Foreword by Jan Mycielski
- Preface
- Preface to the Paperback Edition
- Part I Paradoxical Decompositions, or the Nonexistence of Finitely Additive Measures
- Part II Finitely Additive Measures, or the Nonexistence of Paradoxical Decompositions
- Appendix A Euclidean Transformation Groups
- Appendix B Jordan Measure
- Appendix C Unsolved Problems
- Addendum to Second Printing
- References
- List of Symbols
- Index
Summary
The following is a list of unsolved problems in the area of paradoxical decompositions, equidecomposability, and finitely additive measures. The order represents the author's view as to their interest and importance.
Marczewski's Problem, Circa 1930 (3.12, 9.9)
Is there a finitely additive, isometry-invariant measure on the Borel sets in Sn, n ≥ 2 (or Rn, n ≥ 3), that has total measure one (or, normalizes the unit cube) and vanishes on meager sets? Such a measure cannot be countably additive (9.15), and so by 13.5, it is consistent with ZF + DC that no such finitely additive Borel measure exists. An equivalent problem in the case of R3 is: Is the unit cube paradoxical using pieces that have the Property of Baire?
Tarski's Circle-Squaring Problem, 1924 (7.5)
Is a circle (with interior) in the plane equidecomposable to a square (necessarily of the same area)?
Variations
(a) (p. 102) Can a negative solution be obtained if the pieces are restricted to the Borel sets? It is known that restriction to pieces that are parts of Jordan curves or two-cells (interior of a Jordan curve) yields a negative solution.
(b) (3.14) Is a regular tetrahedron in R3 equidecomposable to a cube using measurable pieces? A restriction to polyhedral pieces yields a negative solution (Hilbert's Third Problem).
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- The Banach-Tarski Paradox , pp. 229 - 233Publisher: Cambridge University PressPrint publication year: 1985