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17 - Gauss's Lemma

Underwood Dudley
Affiliation:
DePauw University
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Summary

Gauss's Lemma is needed to prove the Quadratic Reciprocity Theorem, that for odd primes p and q, (p/q) = (q/p) unless pq ≡ 3 (mod 4), in which case (p/q) = -(q/p), but it also has other uses.

Theorem (Gauss's Lemma) Suppose that p is an odd prime, p ∤ a, and that among the least residues (mod p) of a, 2a, …, ((p-1)/2)a exactly g are greater than (p - 1)/2. Then (a/p) = (-1)g.

Proof Divide the least residues (mod p) of a, 2a, …, ((p - 1)/2)a into two classes: r1, r2, …, rk that are less than or equal to (p - 1)/2 and s1, s2, …, sg that are greater than (p - 1)/2. Then k + g = (p - 1)/2. By Euler's Criterion, to prove the theorem it is enough to show that a(p-1)/2 ≡ (-1)g (mod p).

No two of r1, r2, …, rk are congruent (mod p). If they were we would have k1ak2a (mod p) and, because (a, p) = 1, k1k2 (mod p). Because k1 and k1 are both in the interval [1, (p -1)/2] we have k1 = k1.

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Publisher: Mathematical Association of America
Print publication year: 2009

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  • Gauss's Lemma
  • Underwood Dudley, DePauw University
  • Book: A Guide to Elementary Number Theory
  • Online publication: 05 January 2012
  • Chapter DOI: https://doi.org/10.5948/UPO9780883859186.018
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  • Gauss's Lemma
  • Underwood Dudley, DePauw University
  • Book: A Guide to Elementary Number Theory
  • Online publication: 05 January 2012
  • Chapter DOI: https://doi.org/10.5948/UPO9780883859186.018
Available formats
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Save book to Google Drive

To save content items to your account, please confirm that you agree to abide by our usage policies. If this is the first time you use this feature, you will be asked to authorise Cambridge Core to connect with your account. Find out more about saving content to Google Drive.

  • Gauss's Lemma
  • Underwood Dudley, DePauw University
  • Book: A Guide to Elementary Number Theory
  • Online publication: 05 January 2012
  • Chapter DOI: https://doi.org/10.5948/UPO9780883859186.018
Available formats
×