We prove the existence and give constructions of a
$(p(k)-1)$-fold perfect resolvable
$(v,k,1)$-Mendelsohn design for any integers
$v>k\geq 2$ with
$v\equiv 1\hspace{0.2em}{\rm mod}\hspace{0.2em}\,k$ such that there exists a finite Frobenius group whose kernel
$K$ has order
$v$ and whose complement contains an element
$\unicode[STIX]{x1D719}$ of order
$k$, where
$p(k)$ is the least prime factor of
$k$. Such a design admits
$K\rtimes \langle \unicode[STIX]{x1D719}\rangle$ as a group of automorphisms and is perfect when
$k$ is a prime. As an application we prove that for any integer
$v=p_{1}^{e_{1}}\cdots p_{t}^{e_{t}}\geq 3$ in prime factorisation and any prime
$k$ dividing
$p_{i}^{e_{i}}-1$ for
$1\leq i\leq t$, there exists a resolvable perfect
$(v,k,1)$-Mendelsohn design that admits a Frobenius group as a group of automorphisms. We also prove that, if
$k$ is even and divides
$p_{i}-1$ for
$1\leq i\leq t$, then there are at least
$\unicode[STIX]{x1D711}(k)^{t}$ resolvable
$(v,k,1)$-Mendelsohn designs that admit a Frobenius group as a group of automorphisms, where
$\unicode[STIX]{x1D711}$ is Euler’s totient function.